Base | Representation |
---|---|
bin | 100010111001111100001… |
… | …1011010010010110011001 |
3 | 121222121210200000212112221 |
4 | 1011303320123102112121 |
5 | 1112044433424424303 |
6 | 14111512305504041 |
7 | 1003411561060522 |
oct | 105637033222631 |
9 | 17877720025487 |
10 | 4797351404953 |
11 | 158a5aa88a738 |
12 | 655913342021 |
13 | 28a5081193b3 |
14 | 12829ba13849 |
15 | 84bcb9bd4bd |
hex | 45cf86d2599 |
4797351404953 has 2 divisors, whose sum is σ = 4797351404954. Its totient is φ = 4797351404952.
The previous prime is 4797351404947. The next prime is 4797351404957. The reversal of 4797351404953 is 3594041537974.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4216628154249 + 580723250704 = 2053443^2 + 762052^2 .
It is a cyclic number.
It is not a de Polignac number, because 4797351404953 - 241 = 2598328149401 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 4797351404891 and 4797351404900.
It is not a weakly prime, because it can be changed into another prime (4797351404957) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2398675702476 + 2398675702477.
It is an arithmetic number, because the mean of its divisors is an integer number (2398675702477).
Almost surely, 24797351404953 is an apocalyptic number.
It is an amenable number.
4797351404953 is a deficient number, since it is larger than the sum of its proper divisors (1).
4797351404953 is an equidigital number, since it uses as much as digits as its factorization.
4797351404953 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 57153600, while the sum is 61.
The spelling of 4797351404953 in words is "four trillion, seven hundred ninety-seven billion, three hundred fifty-one million, four hundred four thousand, nine hundred fifty-three".
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