Base | Representation |
---|---|
bin | 100010111111100011100… |
… | …0110000111111001111011 |
3 | 122000202220221220200020221 |
4 | 1011333013012013321323 |
5 | 1112244132110103301 |
6 | 14121224543000511 |
7 | 1004316426142612 |
oct | 105770706077173 |
9 | 18022827820227 |
10 | 4809408675451 |
11 | 15947278a84a6 |
12 | 658119299137 |
13 | 28b6aa0b3693 |
14 | 128ac309c879 |
15 | 851852a2da1 |
hex | 45fc7187e7b |
4809408675451 has 2 divisors, whose sum is σ = 4809408675452. Its totient is φ = 4809408675450.
The previous prime is 4809408675419. The next prime is 4809408675457. The reversal of 4809408675451 is 1545768049084.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4809408675451 - 25 = 4809408675419 is a prime.
It is a super-3 number, since 3×48094086754513 (a number of 39 digits) contains 333 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 4809408675451.
It is not a weakly prime, because it can be changed into another prime (4809408675457) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2404704337725 + 2404704337726.
It is an arithmetic number, because the mean of its divisors is an integer number (2404704337726).
Almost surely, 24809408675451 is an apocalyptic number.
4809408675451 is a deficient number, since it is larger than the sum of its proper divisors (1).
4809408675451 is an equidigital number, since it uses as much as digits as its factorization.
4809408675451 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 38707200, while the sum is 61.
The spelling of 4809408675451 in words is "four trillion, eight hundred nine billion, four hundred eight million, six hundred seventy-five thousand, four hundred fifty-one".
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