48100541773147 has 4 divisors (see below), whose sum is σ = 48759453304360. Its totient is φ = 47441630241936.

The previous prime is 48100541773111. The next prime is 48100541773159. The reversal of 48100541773147 is 74137714500184.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-48100541773147 is a prime.

It is a super-3 number, since 3×48100541773147³ (a number of 42 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 48100541773094 and 48100541773103.

It is not an unprimeable number, because it can be changed into a prime (48100541773447) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 329455765497 + ... + 329455765642.

It is an arithmetic number, because the mean of its divisors is an integer number (12189863326090).

Almost surely, 2^{48100541773147} is an apocalyptic number.

48100541773147 is a deficient number, since it is larger than the sum of its proper divisors (658911531213).

48100541773147 is an equidigital number, since it uses as much as digits as its factorization.

48100541773147 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 658911531212.

The product of its (nonzero) digits is 2634240, while the sum is 52.

The spelling of 48100541773147 in words is "forty-eight trillion, one hundred billion, five hundred forty-one million, seven hundred seventy-three thousand, one hundred forty-seven".