Search a number
-
+
4820113 is a prime number
BaseRepresentation
bin10010011000110010010001
3100001212221201
4102120302101
52213220423
6251151201
755653544
oct22306221
910055851
104820113
1127a2471
121745501
13cc9c4c
148d685b
156532ad
hex498c91

4820113 has 2 divisors, whose sum is σ = 4820114. Its totient is φ = 4820112.

The previous prime is 4820107. The next prime is 4820131. The reversal of 4820113 is 3110284.

4820113 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

Together with next prime (4820131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2650384 + 2169729 = 1628^2 + 1473^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-4820113 is a prime.

It is not a weakly prime, because it can be changed into another prime (4820173) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2410056 + 2410057.

It is an arithmetic number, because the mean of its divisors is an integer number (2410057).

Almost surely, 24820113 is an apocalyptic number.

It is an amenable number.

4820113 is a deficient number, since it is larger than the sum of its proper divisors (1).

4820113 is an equidigital number, since it uses as much as digits as its factorization.

4820113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 192, while the sum is 19.

The square root of 4820113 is about 2195.4755749040. The cubic root of 4820113 is about 168.9218153107.

Adding to 4820113 its reverse (3110284), we get a palindrome (7930397).

The spelling of 4820113 in words is "four million, eight hundred twenty thousand, one hundred thirteen".