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4830917395657 is a prime number
BaseRepresentation
bin100011001001100100100…
…0111011000010011001001
3122002211102221100212112211
41012103021013120103021
51113122204323130112
614135143125305121
71006010431223653
oct106231107302311
918084387325484
104830917395657
1115a2864a23321
126603205651a1
13290727214762
14129b638b76d3
15859e36dc0a7
hex464c91d84c9

4830917395657 has 2 divisors, whose sum is σ = 4830917395658. Its totient is φ = 4830917395656.

The previous prime is 4830917395631. The next prime is 4830917395663. The reversal of 4830917395657 is 7565937190384.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4830869909776 + 47485881 = 2197924^2 + 6891^2 .

It is a cyclic number.

It is not a de Polignac number, because 4830917395657 - 219 = 4830916871369 is a prime.

It is a super-2 number, since 2×48309173956572 (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 4830917395592 and 4830917395601.

It is not a weakly prime, because it can be changed into another prime (4830917395957) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2415458697828 + 2415458697829.

It is an arithmetic number, because the mean of its divisors is an integer number (2415458697829).

Almost surely, 24830917395657 is an apocalyptic number.

It is an amenable number.

4830917395657 is a deficient number, since it is larger than the sum of its proper divisors (1).

4830917395657 is an equidigital number, since it uses as much as digits as its factorization.

4830917395657 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 171460800, while the sum is 67.

The spelling of 4830917395657 in words is "four trillion, eight hundred thirty billion, nine hundred seventeen million, three hundred ninety-five thousand, six hundred fifty-seven".