48310531 has 2 divisors, whose sum is σ = 48310532. Its totient is φ = 48310530.

The previous prime is 48310499. The next prime is 48310541. The reversal of 48310531 is 13501384.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 48310531 - 2⁵ = 48310499 is a prime.

It is a super-2 number, since 2×48310531² = 4667814811003922, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 48310496 and 48310505.

It is not a weakly prime, because it can be changed into another prime (48310541) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24155265 + 24155266.

It is an arithmetic number, because the mean of its divisors is an integer number (24155266).

Almost surely, 2^48310531 is an apocalyptic number.

48310531 is a deficient number, since it is larger than the sum of its proper divisors (1).

48310531 is an equidigital number, since it uses as much as digits as its factorization.

48310531 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1440, while the sum is 25.

The square root of 48310531 is about 6950.5777457705. The cubic root of 48310531 is about 364.2061460607.

It can be divided in two parts, 48310 and 531, that added together give a square (48841 = 221²).

The spelling of 48310531 in words is "forty-eight million, three hundred ten thousand, five hundred thirty-one".