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48312318347 = 174143277429
BaseRepresentation
bin101100111111101000…
…110111100110001011
311121200222011001121222
4230333220313212023
51242420423141342
634105552352255
73330136634036
oct547750674613
9147628131558
1048312318347
1119542053927
12944384568b
13472c217327
1424a453401d
1513cb625ed2
hexb3fa3798b

48312318347 has 4 divisors (see below), whose sum is σ = 48312769920. Its totient is φ = 48311866776.

The previous prime is 48312318323. The next prime is 48312318367. The reversal of 48312318347 is 74381321384.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 48312318347 - 222 = 48308124043 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 48312318298 and 48312318307.

It is not an unprimeable number, because it can be changed into a prime (48312318367) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 35429 + ... + 312857.

It is an arithmetic number, because the mean of its divisors is an integer number (12078192480).

Almost surely, 248312318347 is an apocalyptic number.

48312318347 is a deficient number, since it is larger than the sum of its proper divisors (451573).

48312318347 is a wasteful number, since it uses less digits than its factorization.

48312318347 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 451572.

The product of its digits is 387072, while the sum is 44.

The spelling of 48312318347 in words is "forty-eight billion, three hundred twelve million, three hundred eighteen thousand, three hundred forty-seven".

Divisors: 1 174143 277429 48312318347