Base | Representation |
---|---|
bin | 101101000000001110… |
… | …001011110110100001 |
3 | 11121201122120001102011 |
4 | 231000032023312201 |
5 | 1242430424210031 |
6 | 34110542152521 |
7 | 3330316035613 |
oct | 550016136641 |
9 | 147648501364 |
10 | 48322100641 |
11 | 19547625471 |
12 | 9446b82741 |
13 | 4731260a79 |
14 | 24a595cdb3 |
15 | 13cc4096b1 |
hex | b4038bda1 |
48322100641 has 2 divisors, whose sum is σ = 48322100642. Its totient is φ = 48322100640.
The previous prime is 48322100633. The next prime is 48322100731. The reversal of 48322100641 is 14600122384.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 24673812241 + 23648288400 = 157079^2 + 153780^2 .
It is a cyclic number.
It is not a de Polignac number, because 48322100641 - 23 = 48322100633 is a prime.
It is a super-2 number, since 2×483221006412 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (48322160641) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24161050320 + 24161050321.
It is an arithmetic number, because the mean of its divisors is an integer number (24161050321).
Almost surely, 248322100641 is an apocalyptic number.
It is an amenable number.
48322100641 is a deficient number, since it is larger than the sum of its proper divisors (1).
48322100641 is an equidigital number, since it uses as much as digits as its factorization.
48322100641 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9216, while the sum is 31.
The spelling of 48322100641 in words is "forty-eight billion, three hundred twenty-two million, one hundred thousand, six hundred forty-one".
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