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483437131 is a prime number
BaseRepresentation
bin11100110100001…
…010101001001011
31020200200011001221
4130310022221023
51442224442011
6115545422511
714660101462
oct3464125113
91220604057
10483437131
11228984521
12115a9aa37
1379206298
14482c39d9
152c695971
hex1cd0aa4b

483437131 has 2 divisors, whose sum is σ = 483437132. Its totient is φ = 483437130.

The previous prime is 483437117. The next prime is 483437137. The reversal of 483437131 is 131734384.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-483437131 is a prime.

It is a super-2 number, since 2×4834371312 = 467422919259022322, which contains 22 as substring.

It is equal to p25528291 and since 483437131 and 25528291 have the same sum of digits, it is a Honaker prime.

It is not a weakly prime, because it can be changed into another prime (483437137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 241718565 + 241718566.

It is an arithmetic number, because the mean of its divisors is an integer number (241718566).

Almost surely, 2483437131 is an apocalyptic number.

483437131 is a deficient number, since it is larger than the sum of its proper divisors (1).

483437131 is an equidigital number, since it uses as much as digits as its factorization.

483437131 is an evil number, because the sum of its binary digits is even.

The product of its digits is 24192, while the sum is 34.

The square root of 483437131 is about 21987.2038013022. The cubic root of 483437131 is about 784.8379618757.

The spelling of 483437131 in words is "four hundred eighty-three million, four hundred thirty-seven thousand, one hundred thirty-one".