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483480186740113 is a prime number
BaseRepresentation
bin110110111101110010000000…
…0110010010101110110010001
32100101212020212111110020111011
41231323210000302111312101
51001332314410301140423
64432135422003250521
7203560201511212363
oct15573440062256621
92311766774406434
10483480186740113
11130062883126562
1246285848379a41
13179a0ca82769c4
1487567ccb62d33
153ad666875db0d
hex1b7b900c95d91

483480186740113 has 2 divisors, whose sum is σ = 483480186740114. Its totient is φ = 483480186740112.

The previous prime is 483480186740099. The next prime is 483480186740129. The reversal of 483480186740113 is 311047681084384.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 376940982441024 + 106539204299089 = 19414968^2 + 10321783^2 .

It is a cyclic number.

It is not a de Polignac number, because 483480186740113 - 29 = 483480186739601 is a prime.

It is not a weakly prime, because it can be changed into another prime (483480186740413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 241740093370056 + 241740093370057.

It is an arithmetic number, because the mean of its divisors is an integer number (241740093370057).

Almost surely, 2483480186740113 is an apocalyptic number.

It is an amenable number.

483480186740113 is a deficient number, since it is larger than the sum of its proper divisors (1).

483480186740113 is an equidigital number, since it uses as much as digits as its factorization.

483480186740113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12386304, while the sum is 58.

The spelling of 483480186740113 in words is "four hundred eighty-three trillion, four hundred eighty billion, one hundred eighty-six million, seven hundred forty thousand, one hundred thirteen".