Base | Representation |
---|---|
bin | 101101000010011010… |
… | …111111011101001011 |
3 | 11121211020000100111212 |
4 | 231002122333131023 |
5 | 1243014401342141 |
6 | 34114341243335 |
7 | 3331244551451 |
oct | 550232773513 |
9 | 147736010455 |
10 | 48359012171 |
11 | 19566446668 |
12 | 945740354b |
13 | 4738ab5902 |
14 | 24aa80a9d1 |
15 | 13d079b2eb |
hex | b426bf74b |
48359012171 has 2 divisors, whose sum is σ = 48359012172. Its totient is φ = 48359012170.
The previous prime is 48359012159. The next prime is 48359012179. The reversal of 48359012171 is 17121095384.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-48359012171 is a prime.
It is a super-2 number, since 2×483590121712 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (48359012179) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24179506085 + 24179506086.
It is an arithmetic number, because the mean of its divisors is an integer number (24179506086).
Almost surely, 248359012171 is an apocalyptic number.
48359012171 is a deficient number, since it is larger than the sum of its proper divisors (1).
48359012171 is an equidigital number, since it uses as much as digits as its factorization.
48359012171 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 60480, while the sum is 41.
The spelling of 48359012171 in words is "forty-eight billion, three hundred fifty-nine million, twelve thousand, one hundred seventy-one".
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