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483995884481 is a prime number
BaseRepresentation
bin1110000101100000110…
…01110001101111000001
31201021021111122102000022
413002300121301233001
530412210421300411
61010202235303225
746652604065414
oct7026031615701
91637244572008
10483995884481
1117729707164a
12799752aab15
1336843583535
14195d58ddb7b
15c8caac7edb
hex70b0671bc1

483995884481 has 2 divisors, whose sum is σ = 483995884482. Its totient is φ = 483995884480.

The previous prime is 483995884469. The next prime is 483995884549. The reversal of 483995884481 is 184488599384.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 316400625025 + 167595259456 = 562495^2 + 409384^2 .

It is a cyclic number.

It is not a de Polignac number, because 483995884481 - 26 = 483995884417 is a prime.

It is a super-2 number, since 2×4839958844812 (a number of 24 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (483995884451) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 241997942240 + 241997942241.

It is an arithmetic number, because the mean of its divisors is an integer number (241997942241).

Almost surely, 2483995884481 is an apocalyptic number.

It is an amenable number.

483995884481 is a deficient number, since it is larger than the sum of its proper divisors (1).

483995884481 is an equidigital number, since it uses as much as digits as its factorization.

483995884481 is an evil number, because the sum of its binary digits is even.

The product of its digits is 318504960, while the sum is 71.

The spelling of 483995884481 in words is "four hundred eighty-three billion, nine hundred ninety-five million, eight hundred eighty-four thousand, four hundred eighty-one".