Base | Representation |
---|---|
bin | 110111001001010010010100… |
… | …1000011111010011011011011 |
3 | 2100121110102021200201210221212 |
4 | 1232102210221003322123123 |
5 | 1002034221232030244323 |
6 | 4435350045150053335 |
7 | 204112346635442105 |
oct | 15622445103723333 |
9 | 2317412250653855 |
10 | 485061410399963 |
11 | 130612430711761 |
12 | 464a0198aaa24b |
13 | 17a871301817a7 |
14 | 87ad151896575 |
15 | 3b12861737b78 |
hex | 1b929290fa6db |
485061410399963 has 2 divisors, whose sum is σ = 485061410399964. Its totient is φ = 485061410399962.
The previous prime is 485061410399927. The next prime is 485061410400001. The reversal of 485061410399963 is 369993014160584.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 485061410399963 - 226 = 485061343291099 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 485061410399893 and 485061410399902.
It is not a weakly prime, because it can be changed into another prime (485061410399903) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 242530705199981 + 242530705199982.
It is an arithmetic number, because the mean of its divisors is an integer number (242530705199982).
Almost surely, 2485061410399963 is an apocalyptic number.
485061410399963 is a deficient number, since it is larger than the sum of its proper divisors (1).
485061410399963 is an equidigital number, since it uses as much as digits as its factorization.
485061410399963 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 151165440, while the sum is 68.
The spelling of 485061410399963 in words is "four hundred eighty-five trillion, sixty-one billion, four hundred ten million, three hundred ninety-nine thousand, nine hundred sixty-three".
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