Base | Representation |
---|---|
bin | 100011010011001010000… |
… | …1110111001110100110011 |
3 | 122011210120201121010220112 |
4 | 1012212110032321310303 |
5 | 1113441340240341034 |
6 | 14152430045331535 |
7 | 1010336550122051 |
oct | 106462416716463 |
9 | 18153521533815 |
10 | 4851505012019 |
11 | 160056a1121a6 |
12 | 664307266bab |
13 | 292658570483 |
14 | 12ab57c411d1 |
15 | 862ead2b7ce |
hex | 469943b9d33 |
4851505012019 has 2 divisors, whose sum is σ = 4851505012020. Its totient is φ = 4851505012018.
The previous prime is 4851505012001. The next prime is 4851505012027. The reversal of 4851505012019 is 9102105051584.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4851505012019 is a prime.
It is a super-2 number, since 2×48515050120192 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (4851505012819) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2425752506009 + 2425752506010.
It is an arithmetic number, because the mean of its divisors is an integer number (2425752506010).
Almost surely, 24851505012019 is an apocalyptic number.
4851505012019 is a deficient number, since it is larger than the sum of its proper divisors (1).
4851505012019 is an equidigital number, since it uses as much as digits as its factorization.
4851505012019 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72000, while the sum is 41.
The spelling of 4851505012019 in words is "four trillion, eight hundred fifty-one billion, five hundred five million, twelve thousand, nineteen".
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