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485243011438033 = 1260313850187743
BaseRepresentation
bin110111001010100110111000…
…1010100111001010111010001
32100122002210000210010101112211
41232111031301110321113101
51002100210141412004113
64440005321222352121
7204131436115004512
oct15625156124712721
92318083023111484
10485243011438033
111306824507744a2
124650b41a88b641
1317a9b2b1703434
1487b7c5c176a09
153b1743e797b3d
hex1b953715395d1

485243011438033 has 4 divisors (see below), whose sum is σ = 485246861751808. Its totient is φ = 485239161124260.

The previous prime is 485243011437937. The next prime is 485243011438061. The reversal of 485243011438033 is 330834110342584.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-485243011438033 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (485243011438093) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1924967841 + ... + 1925219902.

It is an arithmetic number, because the mean of its divisors is an integer number (121311715437952).

Almost surely, 2485243011438033 is an apocalyptic number.

It is an amenable number.

485243011438033 is a deficient number, since it is larger than the sum of its proper divisors (3850313775).

485243011438033 is a wasteful number, since it uses less digits than its factorization.

485243011438033 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3850313774.

The product of its (nonzero) digits is 3317760, while the sum is 49.

The spelling of 485243011438033 in words is "four hundred eighty-five trillion, two hundred forty-three billion, eleven million, four hundred thirty-eight thousand, thirty-three".

Divisors: 1 126031 3850187743 485243011438033