Base | Representation |
---|---|
bin | 1110001000000001000… |
… | …11111111110101010011 |
3 | 1201101202020020012021001 |
4 | 13010000203333311103 |
5 | 30422434212202242 |
6 | 1010543520242431 |
7 | 50031124141636 |
oct | 7040043776523 |
9 | 1641666205231 |
10 | 485340740947 |
11 | 177917217177 |
12 | 7a08b770417 |
13 | 369c90956aa |
14 | 196c2379c1d |
15 | c958bc8eb7 |
hex | 71008ffd53 |
485340740947 has 2 divisors, whose sum is σ = 485340740948. Its totient is φ = 485340740946.
The previous prime is 485340740881. The next prime is 485340740953. The reversal of 485340740947 is 749047043584.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-485340740947 is a prime.
It is not a weakly prime, because it can be changed into another prime (485340740447) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 242670370473 + 242670370474.
It is an arithmetic number, because the mean of its divisors is an integer number (242670370474).
Almost surely, 2485340740947 is an apocalyptic number.
485340740947 is a deficient number, since it is larger than the sum of its proper divisors (1).
485340740947 is an equidigital number, since it uses as much as digits as its factorization.
485340740947 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13547520, while the sum is 55.
The spelling of 485340740947 in words is "four hundred eighty-five billion, three hundred forty million, seven hundred forty thousand, nine hundred forty-seven".
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