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4859341197457 is a prime number
BaseRepresentation
bin100011010110110011101…
…0011100101000010010001
3122012112210211202121110211
41012231213103211002101
51114103412321304312
614200203414124121
71011035001444535
oct106554723450221
918175724677424
104859341197457
11160392047230a
12665933650641
13293306b887a6
1412b29c865bc5
1586608c693a7
hex46b674e5091

4859341197457 has 2 divisors, whose sum is σ = 4859341197458. Its totient is φ = 4859341197456.

The previous prime is 4859341197439. The next prime is 4859341197499. The reversal of 4859341197457 is 7547911439584.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 4807775416896 + 51565780561 = 2192664^2 + 227081^2 .

It is a cyclic number.

It is not a de Polignac number, because 4859341197457 - 27 = 4859341197329 is a prime.

It is a super-2 number, since 2×48593411974572 (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 4859341197392 and 4859341197401.

It is not a weakly prime, because it can be changed into another prime (4859341197407) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2429670598728 + 2429670598729.

It is an arithmetic number, because the mean of its divisors is an integer number (2429670598729).

Almost surely, 24859341197457 is an apocalyptic number.

It is an amenable number.

4859341197457 is a deficient number, since it is larger than the sum of its proper divisors (1).

4859341197457 is an equidigital number, since it uses as much as digits as its factorization.

4859341197457 is an evil number, because the sum of its binary digits is even.

The product of its digits is 152409600, while the sum is 67.

The spelling of 4859341197457 in words is "four trillion, eight hundred fifty-nine billion, three hundred forty-one million, one hundred ninety-seven thousand, four hundred fifty-seven".