Base | Representation |
---|---|
bin | 1110001001110100110… |
… | …01100110001111111001 |
3 | 1201111020212010012100220 |
4 | 13010322121212033321 |
5 | 30431431114440431 |
6 | 1011224102250253 |
7 | 50064146042241 |
oct | 7047231461771 |
9 | 1644225105326 |
10 | 486311093241 |
11 | 178274a30216 |
12 | 7a300726989 |
13 | 36b2212204c |
14 | 197751aab21 |
15 | c9b3ea0b96 |
hex | 713a6663f9 |
486311093241 has 4 divisors (see below), whose sum is σ = 648414790992. Its totient is φ = 324207395492.
The previous prime is 486311093197. The next prime is 486311093263. The reversal of 486311093241 is 142390113684.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 486311093241 - 213 = 486311085049 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 486311093193 and 486311093202.
It is not an unprimeable number, because it can be changed into a prime (486311093291) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 81051848871 + ... + 81051848876.
It is an arithmetic number, because the mean of its divisors is an integer number (162103697748).
Almost surely, 2486311093241 is an apocalyptic number.
It is an amenable number.
486311093241 is a deficient number, since it is larger than the sum of its proper divisors (162103697751).
486311093241 is a wasteful number, since it uses less digits than its factorization.
486311093241 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 162103697750.
The product of its (nonzero) digits is 124416, while the sum is 42.
The spelling of 486311093241 in words is "four hundred eighty-six billion, three hundred eleven million, ninety-three thousand, two hundred forty-one".
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