Search a number
-
+
48643302049 is a prime number
BaseRepresentation
bin101101010011010111…
…011110001010100001
311122120000221202220121
4231103113132022201
51244110141131144
634202454440241
73341266150066
oct552327361241
9148500852817
1048643302049
11196a196a881
129516663081
134782972a84
1424d6490c6d
1513ea705384
hexb535de2a1

48643302049 has 2 divisors, whose sum is σ = 48643302050. Its totient is φ = 48643302048.

The previous prime is 48643302013. The next prime is 48643302083. The reversal of 48643302049 is 94020334684.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 25931305024 + 22711997025 = 161032^2 + 150705^2 .

It is a cyclic number.

It is not a de Polignac number, because 48643302049 - 215 = 48643269281 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 48643301996 and 48643302014.

It is not a weakly prime, because it can be changed into another prime (48643309049) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24321651024 + 24321651025.

It is an arithmetic number, because the mean of its divisors is an integer number (24321651025).

Almost surely, 248643302049 is an apocalyptic number.

It is an amenable number.

48643302049 is a deficient number, since it is larger than the sum of its proper divisors (1).

48643302049 is an equidigital number, since it uses as much as digits as its factorization.

48643302049 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 497664, while the sum is 43.

The spelling of 48643302049 in words is "forty-eight billion, six hundred forty-three million, three hundred two thousand, forty-nine".