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487706281132537 is a prime number
BaseRepresentation
bin110111011100100001111011…
…1101001000100000111111001
32100221211021011021122002220101
41232321003313221010013321
51002411034430432220122
64445133101132555401
7204504421203643405
oct15671036751040771
92327737137562811
10487706281132537
1113144208824a5a5
12468488b2922b61
1317c1967456429c
148861177a0a105
153b5b55d98a027
hex1bb90f7a441f9

487706281132537 has 2 divisors, whose sum is σ = 487706281132538. Its totient is φ = 487706281132536.

The previous prime is 487706281132439. The next prime is 487706281132541. The reversal of 487706281132537 is 735231182607784.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 275137725100176 + 212568556032361 = 16587276^2 + 14579731^2 .

It is a cyclic number.

It is not a de Polignac number, because 487706281132537 - 211 = 487706281130489 is a prime.

It is a super-2 number, since 2×4877062811325372 (a number of 30 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (487706281132547) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 243853140566268 + 243853140566269.

It is an arithmetic number, because the mean of its divisors is an integer number (243853140566269).

Almost surely, 2487706281132537 is an apocalyptic number.

It is an amenable number.

487706281132537 is a deficient number, since it is larger than the sum of its proper divisors (1).

487706281132537 is an equidigital number, since it uses as much as digits as its factorization.

487706281132537 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 94832640, while the sum is 64.

The spelling of 487706281132537 in words is "four hundred eighty-seven trillion, seven hundred six billion, two hundred eighty-one million, one hundred thirty-two thousand, five hundred thirty-seven".