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4887568913042 = 22443784456521
BaseRepresentation
bin100011100011111100111…
…0011110001001010010010
3122022020200002012010200102
41013013321303301022102
51120034220120204132
614221152420052402
71013054341201454
oct107077163611222
918266602163612
104887568913042
111614896261882
1266b2b0b34102
13295b85015a8a
1412c7b97702d4
158720beb1c62
hex471f9cf1292

4887568913042 has 4 divisors (see below), whose sum is σ = 7331353369566. Its totient is φ = 2443784456520.

The previous prime is 4887568913023. The next prime is 4887568913047. The reversal of 4887568913042 is 2403198657884.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 4415213740081 + 472355172961 = 2101241^2 + 687281^2 .

It is a self number, because there is not a number n which added to its sum of digits gives 4887568913042.

It is not an unprimeable number, because it can be changed into a prime (4887568913047) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1221892228259 + ... + 1221892228262.

It is a 2-persistent number, because it is pandigital, and so is 2⋅4887568913042 = 9775137826084, but 3⋅4887568913042 = 14662706739126 is not.

Almost surely, 24887568913042 is an apocalyptic number.

4887568913042 is a deficient number, since it is larger than the sum of its proper divisors (2443784456524).

4887568913042 is a wasteful number, since it uses less digits than its factorization.

4887568913042 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2443784456523.

The product of its (nonzero) digits is 92897280, while the sum is 65.

The spelling of 4887568913042 in words is "four trillion, eight hundred eighty-seven billion, five hundred sixty-eight million, nine hundred thirteen thousand, forty-two".

Divisors: 1 2 2443784456521 4887568913042