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490300515131 = 770042930733
BaseRepresentation
bin1110010001010000011…
…00000010001100111011
31201212112212220211101012
413020220030002030323
531013113412441011
61013124013344135
750265050420660
oct7105014021473
91655485824335
10490300515131
11179a319499a9
127b03479804b
13373097aba0b
1419a32d69a67
15cb49336a8b
hex722830233b

490300515131 has 4 divisors (see below), whose sum is σ = 560343445872. Its totient is φ = 420257584392.

The previous prime is 490300515113. The next prime is 490300515137. The reversal of 490300515131 is 131515003094.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 490300515131 - 222 = 490296320827 is a prime.

It is a super-2 number, since 2×4903005151312 (a number of 24 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (490300515137) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 35021465360 + ... + 35021465373.

It is an arithmetic number, because the mean of its divisors is an integer number (140085861468).

Almost surely, 2490300515131 is an apocalyptic number.

490300515131 is a deficient number, since it is larger than the sum of its proper divisors (70042930741).

490300515131 is an equidigital number, since it uses as much as digits as its factorization.

490300515131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 70042930740.

The product of its (nonzero) digits is 8100, while the sum is 32.

The spelling of 490300515131 in words is "four hundred ninety billion, three hundred million, five hundred fifteen thousand, one hundred thirty-one".

Divisors: 1 7 70042930733 490300515131