Base | Representation |
---|---|
bin | 10110010010111110010101… |
… | …01010010010100010111011 |
3 | 20102121021011111002220111221 |
4 | 23021133022222102202323 |
5 | 22411303331123024413 |
6 | 252140140101532511 |
7 | 13220222205421234 |
oct | 1311371252224273 |
9 | 212537144086457 |
10 | 49030451767483 |
11 | 1469377488a88a |
12 | 55ba51b114137 |
13 | 21487232b7884 |
14 | c1712d60808b |
15 | 5a05dba0e68d |
hex | 2c97caa928bb |
49030451767483 has 2 divisors, whose sum is σ = 49030451767484. Its totient is φ = 49030451767482.
The previous prime is 49030451767369. The next prime is 49030451767487. The reversal of 49030451767483 is 38476715403094.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 49030451767483 - 233 = 49021861832891 is a prime.
It is not a weakly prime, because it can be changed into another prime (49030451767487) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24515225883741 + 24515225883742.
It is an arithmetic number, because the mean of its divisors is an integer number (24515225883742).
Almost surely, 249030451767483 is an apocalyptic number.
49030451767483 is a deficient number, since it is larger than the sum of its proper divisors (1).
49030451767483 is an equidigital number, since it uses as much as digits as its factorization.
49030451767483 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 60963840, while the sum is 61.
The spelling of 49030451767483 in words is "forty-nine trillion, thirty billion, four hundred fifty-one million, seven hundred sixty-seven thousand, four hundred eighty-three".
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