Base | Representation |
---|---|
bin | 100011101011111111101… |
… | …1001011100000011110001 |
3 | 122100220020220120110210201 |
4 | 1013113333121130003301 |
5 | 1120330104142341340 |
6 | 14233130433555201 |
7 | 1014235366503613 |
oct | 107277731340361 |
9 | 18326226513721 |
10 | 4904842543345 |
11 | 162114a8239a8 |
12 | 672711a15b01 |
13 | 2976a89034b4 |
14 | 12d57791adb3 |
15 | 878bd6d979a |
hex | 475ff65c0f1 |
4904842543345 has 16 divisors (see below), whose sum is σ = 5915883148560. Its totient is φ = 3903827284224.
The previous prime is 4904842543339. The next prime is 4904842543351. The reversal of 4904842543345 is 5433452484094.
It is an interprime number because it is at equal distance from previous prime (4904842543339) and next prime (4904842543351).
It can be written as a sum of positive squares in 8 ways, for example, as 268555077729 + 4636287465616 = 518223^2 + 2153204^2 .
It is a cyclic number.
It is not a de Polignac number, because 4904842543345 - 225 = 4904808988913 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 39547891 + ... + 39671719.
It is an arithmetic number, because the mean of its divisors is an integer number (369742696785).
Almost surely, 24904842543345 is an apocalyptic number.
It is an amenable number.
4904842543345 is a deficient number, since it is larger than the sum of its proper divisors (1011040605215).
4904842543345 is a wasteful number, since it uses less digits than its factorization.
4904842543345 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 164244.
The product of its (nonzero) digits is 33177600, while the sum is 55.
The spelling of 4904842543345 in words is "four trillion, nine hundred four billion, eight hundred forty-two million, five hundred forty-three thousand, three hundred forty-five".
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