Base | Representation |
---|---|
bin | 110111110000110111000100… |
… | …1110100101100111001101011 |
3 | 2101022201101102120122102010122 |
4 | 1233201232021310230321223 |
5 | 1003242324421333232313 |
6 | 4455112445054433455 |
7 | 205213326466560143 |
oct | 15741561164547153 |
9 | 2338641376572118 |
10 | 490500462399083 |
11 | 13231a094781554 |
12 | 4701a33850288b |
13 | 1808ccc2404776 |
14 | 891a4c5b19923 |
15 | 3ba9098eca708 |
hex | 1be1b89d2ce6b |
490500462399083 has 2 divisors, whose sum is σ = 490500462399084. Its totient is φ = 490500462399082.
The previous prime is 490500462399071. The next prime is 490500462399107. The reversal of 490500462399083 is 380993264005094.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 490500462399083 - 214 = 490500462382699 is a prime.
It is a super-2 number, since 2×4905004623990832 (a number of 30 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (490500462309083) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 245250231199541 + 245250231199542.
It is an arithmetic number, because the mean of its divisors is an integer number (245250231199542).
Almost surely, 2490500462399083 is an apocalyptic number.
490500462399083 is a deficient number, since it is larger than the sum of its proper divisors (1).
490500462399083 is an equidigital number, since it uses as much as digits as its factorization.
490500462399083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 50388480, while the sum is 62.
The spelling of 490500462399083 in words is "four hundred ninety trillion, five hundred billion, four hundred sixty-two million, three hundred ninety-nine thousand, eighty-three".
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