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4907213325041 = 6029381389437
BaseRepresentation
bin100011101101000110010…
…1101010000001011110001
3122101010101010121122220012
41013122030231100023301
51120344433102400131
614234202004024305
71014351215015606
oct107321455201361
918333333548805
104907213325041
111622156a9a315
12673073992095
13297995b2bbc1
1412d7207326ad
15879ab8dd52b
hex4768cb502f1

4907213325041 has 4 divisors (see below), whose sum is σ = 4907294774772. Its totient is φ = 4907131875312.

The previous prime is 4907213325037. The next prime is 4907213325073. The reversal of 4907213325041 is 1405233127094.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 733789258225 + 4173424066816 = 856615^2 + 2042896^2 .

It is a cyclic number.

It is not a de Polignac number, because 4907213325041 - 22 = 4907213325037 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 4907213325041.

It is not an unprimeable number, because it can be changed into a prime (4907213325011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 40634426 + ... + 40755011.

It is an arithmetic number, because the mean of its divisors is an integer number (1226823693693).

Almost surely, 24907213325041 is an apocalyptic number.

It is an amenable number.

4907213325041 is a deficient number, since it is larger than the sum of its proper divisors (81449731).

4907213325041 is an equidigital number, since it uses as much as digits as its factorization.

4907213325041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 81449730.

The product of its (nonzero) digits is 181440, while the sum is 41.

The spelling of 4907213325041 in words is "four trillion, nine hundred seven billion, two hundred thirteen million, three hundred twenty-five thousand, forty-one".

Divisors: 1 60293 81389437 4907213325041