Base | Representation |
---|---|
bin | 10110010100010100010110… |
… | …01010000110010001101011 |
3 | 20102202200100210111012100001 |
4 | 23022022023022012101223 |
5 | 22413032420014114032 |
6 | 252213254255123431 |
7 | 13223445444436516 |
oct | 1312121312062153 |
9 | 212680323435301 |
10 | 49076631004267 |
11 | 1470131185a989 |
12 | 5607468513577 |
13 | 214cba2600559 |
14 | c1947071dd7d |
15 | 5a18e0c363e7 |
hex | 2ca28b28646b |
49076631004267 has 2 divisors, whose sum is σ = 49076631004268. Its totient is φ = 49076631004266.
The previous prime is 49076631004217. The next prime is 49076631004333. The reversal of 49076631004267 is 76240013667094.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 49076631004267 - 231 = 49074483520619 is a prime.
It is not a weakly prime, because it can be changed into another prime (49076631004207) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24538315502133 + 24538315502134.
It is an arithmetic number, because the mean of its divisors is an integer number (24538315502134).
Almost surely, 249076631004267 is an apocalyptic number.
49076631004267 is a deficient number, since it is larger than the sum of its proper divisors (1).
49076631004267 is an equidigital number, since it uses as much as digits as its factorization.
49076631004267 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9144576, while the sum is 55.
The spelling of 49076631004267 in words is "forty-nine trillion, seventy-six billion, six hundred thirty-one million, four thousand, two hundred sixty-seven".
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