Base | Representation |
---|---|
bin | 1001001001001101… |
… | …10110111010000011 |
3 | 110200010101211002011 |
4 | 10210212312322003 |
5 | 40023214232233 |
6 | 2131043433351 |
7 | 232436642254 |
oct | 44446667203 |
9 | 13603354064 |
10 | 4909133443 |
11 | 209a094685 |
12 | b50085857 |
13 | 6030953b6 |
14 | 347daab2b |
15 | 1daea80cd |
hex | 1249b6e83 |
4909133443 has 2 divisors, whose sum is σ = 4909133444. Its totient is φ = 4909133442.
The previous prime is 4909133353. The next prime is 4909133447. The reversal of 4909133443 is 3443319094.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4909133443 - 213 = 4909125251 is a prime.
It is a super-2 number, since 2×49091334432 = 48199182322362068498, which contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 4909133396 and 4909133405.
It is not a weakly prime, because it can be changed into another prime (4909133447) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2454566721 + 2454566722.
It is an arithmetic number, because the mean of its divisors is an integer number (2454566722).
Almost surely, 24909133443 is an apocalyptic number.
4909133443 is a deficient number, since it is larger than the sum of its proper divisors (1).
4909133443 is an equidigital number, since it uses as much as digits as its factorization.
4909133443 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 139968, while the sum is 40.
The square root of 4909133443 is about 70065.2085060767. The cubic root of 4909133443 is about 1699.5539132898.
The spelling of 4909133443 in words is "four billion, nine hundred nine million, one hundred thirty-three thousand, four hundred forty-three".
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