Base | Representation |
---|---|
bin | 10110010101010100001011… |
… | …10000110100100001100011 |
3 | 20102212221211002002020202202 |
4 | 23022222011300310201203 |
5 | 22414113110424331433 |
6 | 252241122555403415 |
7 | 13226100614160365 |
oct | 1312520560644143 |
9 | 212787732066682 |
10 | 49110900230243 |
11 | 147148a7952645 |
12 | 561203115356b |
13 | 21531a42cb767 |
14 | c1ada1b60d35 |
15 | 5a2749565ee8 |
hex | 2caa85c34863 |
49110900230243 has 2 divisors, whose sum is σ = 49110900230244. Its totient is φ = 49110900230242.
The previous prime is 49110900230221. The next prime is 49110900230297. The reversal of 49110900230243 is 34203200901194.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 49110900230243 - 222 = 49110896035939 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 49110900230197 and 49110900230206.
It is not a weakly prime, because it can be changed into another prime (49110900236243) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24555450115121 + 24555450115122.
It is an arithmetic number, because the mean of its divisors is an integer number (24555450115122).
Almost surely, 249110900230243 is an apocalyptic number.
49110900230243 is a deficient number, since it is larger than the sum of its proper divisors (1).
49110900230243 is an equidigital number, since it uses as much as digits as its factorization.
49110900230243 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 46656, while the sum is 38.
The spelling of 49110900230243 in words is "forty-nine trillion, one hundred ten billion, nine hundred million, two hundred thirty thousand, two hundred forty-three".
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