Base | Representation |
---|---|
bin | 100011101110111101000… |
… | …1000101100011101110011 |
3 | 122101111122202002001002102 |
4 | 1013131322020230131303 |
5 | 1120431112330001323 |
6 | 14240101142011015 |
7 | 1014552014220143 |
oct | 107357210543563 |
9 | 18344582061072 |
10 | 4911196718963 |
11 | 1623910571107 |
12 | 6739a5a16a6b |
13 | 29817c187c22 |
14 | 12d9bb7a2923 |
15 | 87b41483328 |
hex | 4777a22c773 |
4911196718963 has 2 divisors, whose sum is σ = 4911196718964. Its totient is φ = 4911196718962.
The previous prime is 4911196718839. The next prime is 4911196718977. The reversal of 4911196718963 is 3698176911194.
4911196718963 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4911196718963 - 230 = 4910122977139 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 4911196718963.
It is not a weakly prime, because it can be changed into another prime (4911196711963) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2455598359481 + 2455598359482.
It is an arithmetic number, because the mean of its divisors is an integer number (2455598359482).
Almost surely, 24911196718963 is an apocalyptic number.
4911196718963 is a deficient number, since it is larger than the sum of its proper divisors (1).
4911196718963 is an equidigital number, since it uses as much as digits as its factorization.
4911196718963 is an evil number, because the sum of its binary digits is even.
The product of its digits is 17635968, while the sum is 65.
The spelling of 4911196718963 in words is "four trillion, nine hundred eleven billion, one hundred ninety-six million, seven hundred eighteen thousand, nine hundred sixty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •