Base | Representation |
---|---|
bin | 110111110101011100111110… |
… | …0001101001110000000000001 |
3 | 2101101221201111020100122101101 |
4 | 1233222321330031032000001 |
5 | 1003333200001044400401 |
6 | 4500314423430134401 |
7 | 205310041514046214 |
oct | 15752717415160001 |
9 | 2341851436318341 |
10 | 491131594137601 |
11 | 132542815130a6a |
12 | 471007151b1401 |
13 | 18107683a3b111 |
14 | 893cc7884977b |
15 | 3bba6d6ec7101 |
hex | 1beae7c34e001 |
491131594137601 has 8 divisors (see below), whose sum is σ = 493278384216384. Its totient is φ = 488988798088560.
The previous prime is 491131594137599. The next prime is 491131594137641. The reversal of 491131594137601 is 106731495131194.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 491131594137601 - 21 = 491131594137599 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (491131594137641) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 998260966 + ... + 998752831.
It is an arithmetic number, because the mean of its divisors is an integer number (61659798027048).
Almost surely, 2491131594137601 is an apocalyptic number.
It is an amenable number.
491131594137601 is a deficient number, since it is larger than the sum of its proper divisors (2146790078783).
491131594137601 is a wasteful number, since it uses less digits than its factorization.
491131594137601 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1997014871.
The product of its (nonzero) digits is 2449440, while the sum is 55.
The spelling of 491131594137601 in words is "four hundred ninety-one trillion, one hundred thirty-one billion, five hundred ninety-four million, one hundred thirty-seven thousand, six hundred one".
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