Base | Representation |
---|---|
bin | 100011101111001000100… |
… | …0011000000111101111011 |
3 | 122101112122112100221000221 |
4 | 1013132101003000331323 |
5 | 1120432404230343133 |
6 | 14240203232440511 |
7 | 1014564362364163 |
oct | 107362103007573 |
9 | 18345575327027 |
10 | 4911581106043 |
11 | 1623a98542887 |
12 | 673a926a9137 |
13 | 2982109c0bc1 |
14 | 12da168615a3 |
15 | 87b650b0a2d |
hex | 477910c0f7b |
4911581106043 has 12 divisors (see below), whose sum is σ = 5036568097264. Its totient is φ = 4789625313600.
The previous prime is 4911581106037. The next prime is 4911581106073. The reversal of 4911581106043 is 3406011851194.
It is not a de Polignac number, because 4911581106043 - 233 = 4902991171451 is a prime.
It is a super-3 number, since 3×49115811060433 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (4911581106073) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 3075730 + ... + 4391272.
Almost surely, 24911581106043 is an apocalyptic number.
4911581106043 is a deficient number, since it is larger than the sum of its proper divisors (124986991221).
4911581106043 is a wasteful number, since it uses less digits than its factorization.
4911581106043 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1317846 (or 1317805 counting only the distinct ones).
The product of its (nonzero) digits is 103680, while the sum is 43.
The spelling of 4911581106043 in words is "four trillion, nine hundred eleven billion, five hundred eighty-one million, one hundred six thousand, forty-three".
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