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491217113 is a prime number
BaseRepresentation
bin11101010001110…
…110000011011001
31021020022102012102
4131101312003121
52001222421423
6120424253145
715113163602
oct3521660331
91236272172
10491217113
11232308762
121186111b5
137a9cb51a
144934ada9
152d1d0c28
hex1d4760d9

491217113 has 2 divisors, whose sum is σ = 491217114. Its totient is φ = 491217112.

The previous prime is 491217101. The next prime is 491217149. The reversal of 491217113 is 311712194.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 342694144 + 148522969 = 18512^2 + 12187^2 .

It is a cyclic number.

It is not a de Polignac number, because 491217113 - 218 = 490954969 is a prime.

It is a Sophie Germain prime.

It is a Chen prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (491217173) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 245608556 + 245608557.

It is an arithmetic number, because the mean of its divisors is an integer number (245608557).

Almost surely, 2491217113 is an apocalyptic number.

It is an amenable number.

491217113 is a deficient number, since it is larger than the sum of its proper divisors (1).

491217113 is an equidigital number, since it uses as much as digits as its factorization.

491217113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1512, while the sum is 29.

The square root of 491217113 is about 22163.4183509674. The cubic root of 491217113 is about 789.0257246656.

The spelling of 491217113 in words is "four hundred ninety-one million, two hundred seventeen thousand, one hundred thirteen".