Base | Representation |
---|---|
bin | 100011101111100010100… |
… | …0111101001011101000001 |
3 | 122101121220102020220121012 |
4 | 1013133011013221131001 |
5 | 1120441201403020211 |
6 | 14240430041410305 |
7 | 1014625131202313 |
oct | 107370507513501 |
9 | 18347812226535 |
10 | 4912454735681 |
11 | 16243a66a3749 |
12 | 674097199995 |
13 | 29831c9b370c |
14 | 12da9a8b57b3 |
15 | 87bb6b2dd8b |
hex | 477c51e9741 |
4912454735681 has 2 divisors, whose sum is σ = 4912454735682. Its totient is φ = 4912454735680.
The previous prime is 4912454735663. The next prime is 4912454735689. The reversal of 4912454735681 is 1865374542194.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4396989610000 + 515465125681 = 2096900^2 + 717959^2 .
It is a cyclic number.
It is not a de Polignac number, because 4912454735681 - 222 = 4912450541377 is a prime.
It is a super-2 number, since 2×49124547356812 (a number of 26 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 4912454735681.
It is not a weakly prime, because it can be changed into another prime (4912454735689) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2456227367840 + 2456227367841.
It is an arithmetic number, because the mean of its divisors is an integer number (2456227367841).
Almost surely, 24912454735681 is an apocalyptic number.
It is an amenable number.
4912454735681 is a deficient number, since it is larger than the sum of its proper divisors (1).
4912454735681 is an equidigital number, since it uses as much as digits as its factorization.
4912454735681 is an evil number, because the sum of its binary digits is even.
The product of its digits is 29030400, while the sum is 59.
The spelling of 4912454735681 in words is "four trillion, nine hundred twelve billion, four hundred fifty-four million, seven hundred thirty-five thousand, six hundred eighty-one".
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