4913279449963 has 2 divisors, whose sum is σ = 4913279449964. Its totient is φ = 4913279449962.

The previous prime is 4913279449951. The next prime is 4913279449987. The reversal of 4913279449963 is 3699449723194.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-4913279449963 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 4913279449892 and 4913279449901.

It is not a weakly prime, because it can be changed into another prime (4913279449943) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2456639724981 + 2456639724982.

It is an arithmetic number, because the mean of its divisors is an integer number (2456639724982).

Almost surely, 2^{4913279449963} is an apocalyptic number.

4913279449963 is a deficient number, since it is larger than the sum of its proper divisors (1).

4913279449963 is an equidigital number, since it uses as much as digits as its factorization.

4913279449963 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 317447424, while the sum is 70.

The spelling of 4913279449963 in words is "four trillion, nine hundred thirteen billion, two hundred seventy-nine million, four hundred forty-nine thousand, nine hundred sixty-three".