Base | Representation |
---|---|
bin | 101101110001001010… |
… | …101101100010001011 |
3 | 11200211212201221221212 |
4 | 231301022231202023 |
5 | 1301121134223421 |
6 | 34324234523335 |
7 | 3356546635115 |
oct | 556112554213 |
9 | 150755657855 |
10 | 49143273611 |
11 | 19929107913 |
12 | 9635b9654b |
13 | 4832417c33 |
14 | 2542a3a3b5 |
15 | 1429564e5b |
hex | b712ad88b |
49143273611 has 2 divisors, whose sum is σ = 49143273612. Its totient is φ = 49143273610.
The previous prime is 49143273563. The next prime is 49143273629. The reversal of 49143273611 is 11637234194.
49143273611 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 49143273611 - 26 = 49143273547 is a prime.
It is a super-2 number, since 2×491432736112 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (49143273211) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24571636805 + 24571636806.
It is an arithmetic number, because the mean of its divisors is an integer number (24571636806).
Almost surely, 249143273611 is an apocalyptic number.
49143273611 is a deficient number, since it is larger than the sum of its proper divisors (1).
49143273611 is an equidigital number, since it uses as much as digits as its factorization.
49143273611 is an evil number, because the sum of its binary digits is even.
The product of its digits is 108864, while the sum is 41.
The spelling of 49143273611 in words is "forty-nine billion, one hundred forty-three million, two hundred seventy-three thousand, six hundred eleven".
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