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4914902809009 = 19258679095211
BaseRepresentation
bin100011110000101011100…
…0010010011100110110001
3122101212020000201220212201
41013201113002103212301
51121011210104342014
614241513012223201
71015042605400324
oct107412702234661
918355200656781
104914902809009
111625442560446
1267465b00ab01
1329861cc3180b
1412dc4da8a7bb
1587cab9ede74
hex478570939b1

4914902809009 has 4 divisors (see below), whose sum is σ = 5173581904240. Its totient is φ = 4656223713780.

The previous prime is 4914902809001. The next prime is 4914902809013. The reversal of 4914902809009 is 9009082094194.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 4914902809009 - 23 = 4914902809001 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (4914902809001) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 129339547587 + ... + 129339547624.

It is an arithmetic number, because the mean of its divisors is an integer number (1293395476060).

Almost surely, 24914902809009 is an apocalyptic number.

It is an amenable number.

4914902809009 is a deficient number, since it is larger than the sum of its proper divisors (258679095231).

4914902809009 is a wasteful number, since it uses less digits than its factorization.

4914902809009 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 258679095230.

The product of its (nonzero) digits is 1679616, while the sum is 55.

The spelling of 4914902809009 in words is "four trillion, nine hundred fourteen billion, nine hundred two million, eight hundred nine thousand, nine".

Divisors: 1 19 258679095211 4914902809009