Base | Representation |
---|---|
bin | 1001001001111001… |
… | …11101010001011011 |
3 | 110200112022010220121 |
4 | 10210330331101123 |
5 | 40031210123213 |
6 | 2131411534111 |
7 | 232540121212 |
oct | 44474752133 |
9 | 13615263817 |
10 | 4914926683 |
11 | 20a2391187 |
12 | b51bba337 |
13 | 604343254 |
14 | 348a78079 |
15 | 1db74e88d |
hex | 124f3d45b |
4914926683 has 2 divisors, whose sum is σ = 4914926684. Its totient is φ = 4914926682.
The previous prime is 4914926663. The next prime is 4914926693. The reversal of 4914926683 is 3866294194.
4914926683 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4914926683 - 221 = 4912829531 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 4914926683.
It is not a weakly prime, because it can be changed into another prime (4914926663) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2457463341 + 2457463342.
It is an arithmetic number, because the mean of its divisors is an integer number (2457463342).
Almost surely, 24914926683 is an apocalyptic number.
4914926683 is a deficient number, since it is larger than the sum of its proper divisors (1).
4914926683 is an equidigital number, since it uses as much as digits as its factorization.
4914926683 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2239488, while the sum is 52.
The square root of 4914926683 is about 70106.5380902523. The cubic root of 4914926683 is about 1700.2221950633. Note that the first 3 decimals are identical.
The spelling of 4914926683 in words is "four billion, nine hundred fourteen million, nine hundred twenty-six thousand, six hundred eighty-three".
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