Base | Representation |
---|---|
bin | 10110010110011100011110… |
… | …01001011100001011110001 |
3 | 20110000122222221222222120211 |
4 | 23023032033021130023301 |
5 | 22420232102332303003 |
6 | 252311022142504121 |
7 | 13231643456064661 |
oct | 1313161711341361 |
9 | 213018887888524 |
10 | 49149712384753 |
11 | 1472a3043467a2 |
12 | 5619663295041 |
13 | 2156a4b253c66 |
14 | c1cc046841a1 |
15 | 5a376bb1396d |
hex | 2cb38f25c2f1 |
49149712384753 has 2 divisors, whose sum is σ = 49149712384754. Its totient is φ = 49149712384752.
The previous prime is 49149712384579. The next prime is 49149712384781. The reversal of 49149712384753 is 35748321794194.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 30905683066944 + 18244029317809 = 5559288^2 + 4271303^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-49149712384753 is a prime.
It is not a weakly prime, because it can be changed into another prime (49149712382753) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24574856192376 + 24574856192377.
It is an arithmetic number, because the mean of its divisors is an integer number (24574856192377).
Almost surely, 249149712384753 is an apocalyptic number.
It is an amenable number.
49149712384753 is a deficient number, since it is larger than the sum of its proper divisors (1).
49149712384753 is an equidigital number, since it uses as much as digits as its factorization.
49149712384753 is an evil number, because the sum of its binary digits is even.
The product of its digits is 182891520, while the sum is 67.
The spelling of 49149712384753 in words is "forty-nine trillion, one hundred forty-nine billion, seven hundred twelve million, three hundred eighty-four thousand, seven hundred fifty-three".
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