Base | Representation |
---|---|
bin | 100011110010000001011… |
… | …1100111001010011100001 |
3 | 122102010200000222122111022 |
4 | 1013210002330321103201 |
5 | 1121033111442243323 |
6 | 14243111124055225 |
7 | 1015204230254435 |
oct | 107440274712341 |
9 | 18363600878438 |
10 | 4917787071713 |
11 | 162669266072a |
12 | 675124b34515 |
13 | 29898c652439 |
14 | 130044b669c5 |
15 | 87dc9d304c8 |
hex | 47902f394e1 |
4917787071713 has 4 divisors (see below), whose sum is σ = 4918098517248. Its totient is φ = 4917475626180.
The previous prime is 4917787071707. The next prime is 4917787071731. The reversal of 4917787071713 is 3171707877194.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 4917787071713 - 26 = 4917787071649 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (4917787071763) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 155699081 + ... + 155730662.
It is an arithmetic number, because the mean of its divisors is an integer number (1229524629312).
Almost surely, 24917787071713 is an apocalyptic number.
It is an amenable number.
4917787071713 is a deficient number, since it is larger than the sum of its proper divisors (311445535).
4917787071713 is a wasteful number, since it uses less digits than its factorization.
4917787071713 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 311445534.
The product of its (nonzero) digits is 14521248, while the sum is 62.
The spelling of 4917787071713 in words is "four trillion, nine hundred seventeen billion, seven hundred eighty-seven million, seventy-one thousand, seven hundred thirteen".
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