Base | Representation |
---|---|
bin | 101101110100100110… |
… | …000011101010101001 |
3 | 11200222212221021101112 |
4 | 231310212003222221 |
5 | 1301230344230201 |
6 | 34334051200105 |
7 | 3361145451134 |
oct | 556446035251 |
9 | 150885837345 |
10 | 49200773801 |
11 | 19958610633 |
12 | 96512a6035 |
13 | 48412cb10a |
14 | 254a52721b |
15 | 142e6220bb |
hex | b74983aa9 |
49200773801 has 2 divisors, whose sum is σ = 49200773802. Its totient is φ = 49200773800.
The previous prime is 49200773767. The next prime is 49200773813. The reversal of 49200773801 is 10837700294.
49200773801 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 46289092201 + 2911681600 = 215149^2 + 53960^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-49200773801 is a prime.
It is a super-2 number, since 2×492007738012 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (49200773851) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24600386900 + 24600386901.
It is an arithmetic number, because the mean of its divisors is an integer number (24600386901).
Almost surely, 249200773801 is an apocalyptic number.
It is an amenable number.
49200773801 is a deficient number, since it is larger than the sum of its proper divisors (1).
49200773801 is an equidigital number, since it uses as much as digits as its factorization.
49200773801 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 84672, while the sum is 41.
The spelling of 49200773801 in words is "forty-nine billion, two hundred million, seven hundred seventy-three thousand, eight hundred one".
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