Base | Representation |
---|---|
bin | 10110011000000101000011… |
… | …01111000010110101001001 |
3 | 20110020000220220101202121021 |
4 | 23030002201233002311021 |
5 | 22422142044323311423 |
6 | 252352505351312441 |
7 | 13236002023565311 |
oct | 1314024157026511 |
9 | 213200826352537 |
10 | 49205858807113 |
11 | 147510a6558948 |
12 | 562851267b721 |
13 | 215c128508098 |
14 | c2180d41a441 |
15 | 5a4e55db595d |
hex | 2cc0a1bc2d49 |
49205858807113 has 2 divisors, whose sum is σ = 49205858807114. Its totient is φ = 49205858807112.
The previous prime is 49205858807081. The next prime is 49205858807129. The reversal of 49205858807113 is 31170885850294.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 48100147672329 + 1105711134784 = 6935427^2 + 1051528^2 .
It is a cyclic number.
It is not a de Polignac number, because 49205858807113 - 25 = 49205858807081 is a prime.
It is not a weakly prime, because it can be changed into another prime (49205858807173) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24602929403556 + 24602929403557.
It is an arithmetic number, because the mean of its divisors is an integer number (24602929403557).
Almost surely, 249205858807113 is an apocalyptic number.
It is an amenable number.
49205858807113 is a deficient number, since it is larger than the sum of its proper divisors (1).
49205858807113 is an equidigital number, since it uses as much as digits as its factorization.
49205858807113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 19353600, while the sum is 61.
The spelling of 49205858807113 in words is "forty-nine trillion, two hundred five billion, eight hundred fifty-eight million, eight hundred seven thousand, one hundred thirteen".
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