Base | Representation |
---|---|
bin | 1001001010100101… |
… | …10000001110110001 |
3 | 110200221001102200222 |
4 | 10211102300032301 |
5 | 40034140443213 |
6 | 2132134222425 |
7 | 232636516322 |
oct | 44522601661 |
9 | 13627042628 |
10 | 4920640433 |
11 | 20a5633a95 |
12 | b53ab4a15 |
13 | 605593b77 |
14 | 349724449 |
15 | 1dbecc808 |
hex | 1254b03b1 |
4920640433 has 2 divisors, whose sum is σ = 4920640434. Its totient is φ = 4920640432.
The previous prime is 4920640427. The next prime is 4920640441. The reversal of 4920640433 is 3340460294.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3107839504 + 1812800929 = 55748^2 + 42577^2 .
It is a cyclic number.
It is not a de Polignac number, because 4920640433 - 230 = 3846898609 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 4920640393 and 4920640402.
It is not a weakly prime, because it can be changed into another prime (4920640423) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2460320216 + 2460320217.
It is an arithmetic number, because the mean of its divisors is an integer number (2460320217).
Almost surely, 24920640433 is an apocalyptic number.
It is an amenable number.
4920640433 is a deficient number, since it is larger than the sum of its proper divisors (1).
4920640433 is an equidigital number, since it uses as much as digits as its factorization.
4920640433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 62208, while the sum is 35.
The square root of 4920640433 is about 70147.2767326002. The cubic root of 4920640433 is about 1700.8807930513.
The spelling of 4920640433 in words is "four billion, nine hundred twenty million, six hundred forty thousand, four hundred thirty-three".
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