Base | Representation |
---|---|
bin | 101101110101011101… |
… | …010001101111111011 |
3 | 11201000220011201011221 |
4 | 231311131101233323 |
5 | 1301243100440103 |
6 | 34335325332511 |
7 | 3361412501065 |
oct | 556535215773 |
9 | 151026151157 |
10 | 49215249403 |
11 | 199657a8341 |
12 | 9656107137 |
13 | 48442c8b68 |
14 | 254c414735 |
15 | 1430a311bd |
hex | b75751bfb |
49215249403 has 2 divisors, whose sum is σ = 49215249404. Its totient is φ = 49215249402.
The previous prime is 49215249379. The next prime is 49215249431. The reversal of 49215249403 is 30494251294.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 49215249403 - 229 = 48678378491 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 49215249403.
It is not a weakly prime, because it can be changed into another prime (49215249703) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24607624701 + 24607624702.
It is an arithmetic number, because the mean of its divisors is an integer number (24607624702).
Almost surely, 249215249403 is an apocalyptic number.
49215249403 is a deficient number, since it is larger than the sum of its proper divisors (1).
49215249403 is an equidigital number, since it uses as much as digits as its factorization.
49215249403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 311040, while the sum is 43.
The spelling of 49215249403 in words is "forty-nine billion, two hundred fifteen million, two hundred forty-nine thousand, four hundred three".
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