Base | Representation |
---|---|
bin | 100011110100011101000… |
… | …1001100001011010110001 |
3 | 122102122010220021011021021 |
4 | 1013220322021201122301 |
5 | 1121124310033032141 |
6 | 14245333152455441 |
7 | 1015450505242366 |
oct | 107507211413261 |
9 | 18378126234237 |
10 | 4923008095921 |
11 | 1628921800473 |
12 | 67614154a581 |
13 | 299312219986 |
14 | 1303bc32046d |
15 | 880d33956d1 |
hex | 47a3a2616b1 |
4923008095921 has 4 divisors (see below), whose sum is σ = 5182113785200. Its totient is φ = 4663902406644.
The previous prime is 4923008095829. The next prime is 4923008095961. The reversal of 4923008095921 is 1295908003294.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 4923008095921 - 213 = 4923008087729 is a prime.
It is not an unprimeable number, because it can be changed into a prime (4923008095961) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 129552844611 + ... + 129552844648.
It is an arithmetic number, because the mean of its divisors is an integer number (1295528446300).
Almost surely, 24923008095921 is an apocalyptic number.
It is an amenable number.
4923008095921 is a deficient number, since it is larger than the sum of its proper divisors (259105689279).
4923008095921 is a wasteful number, since it uses less digits than its factorization.
4923008095921 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 259105689278.
The product of its (nonzero) digits is 1399680, while the sum is 52.
The spelling of 4923008095921 in words is "four trillion, nine hundred twenty-three billion, eight million, ninety-five thousand, nine hundred twenty-one".
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