Base | Representation |
---|---|
bin | 101101111010100001… |
… | …011000111100011011 |
3 | 11201020211001100001111 |
4 | 231322201120330123 |
5 | 1301431323313111 |
6 | 34352002401151 |
7 | 3363463620652 |
oct | 557241307433 |
9 | 151224040044 |
10 | 49300213531 |
11 | 199a975a128 |
12 | 967a6601b7 |
13 | 4858aa68aa |
14 | 2559810199 |
15 | 1438215a21 |
hex | b7a858f1b |
49300213531 has 2 divisors, whose sum is σ = 49300213532. Its totient is φ = 49300213530.
The previous prime is 49300213493. The next prime is 49300213549. The reversal of 49300213531 is 13531200394.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 49300213531 - 29 = 49300213019 is a prime.
It is a super-2 number, since 2×493002135312 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 49300213493 and 49300213502.
It is not a weakly prime, because it can be changed into another prime (49300013531) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24650106765 + 24650106766.
It is an arithmetic number, because the mean of its divisors is an integer number (24650106766).
Almost surely, 249300213531 is an apocalyptic number.
49300213531 is a deficient number, since it is larger than the sum of its proper divisors (1).
49300213531 is an equidigital number, since it uses as much as digits as its factorization.
49300213531 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9720, while the sum is 31.
The spelling of 49300213531 in words is "forty-nine billion, three hundred million, two hundred thirteen thousand, five hundred thirty-one".
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