Base | Representation |
---|---|
bin | 10110011011001100101100… |
… | …00101010111110111010011 |
3 | 20110121021120101001022110220 |
4 | 23031212112011113313103 |
5 | 22430421100101004433 |
6 | 252514032515124123 |
7 | 13246515016564044 |
oct | 1315462605276723 |
9 | 213537511038426 |
10 | 49313037516243 |
11 | 147925a60a9406 |
12 | 56452445a3643 |
13 | 2169279361bb7 |
14 | c26a99a368cb |
15 | 5a7b2a46a2b3 |
hex | 2cd996157dd3 |
49313037516243 has 8 divisors (see below), whose sum is σ = 65936979343248. Its totient is φ = 32782227016704.
The previous prime is 49313037516241. The next prime is 49313037516247. The reversal of 49313037516243 is 34261573031394.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 49313037516243 - 21 = 49313037516241 is a prime.
It is a super-4 number, since 4×493130375162434 (a number of 56 digits) contains 4444 as substring.
It is not an unprimeable number, because it can be changed into a prime (49313037516241) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 23282830630 + ... + 23282832747.
It is an arithmetic number, because the mean of its divisors is an integer number (8242122417906).
Almost surely, 249313037516243 is an apocalyptic number.
49313037516243 is a deficient number, since it is larger than the sum of its proper divisors (16623941827005).
49313037516243 is a wasteful number, since it uses less digits than its factorization.
49313037516243 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 46565663733.
The product of its (nonzero) digits is 4898880, while the sum is 51.
The spelling of 49313037516243 in words is "forty-nine trillion, three hundred thirteen billion, thirty-seven million, five hundred sixteen thousand, two hundred forty-three".
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