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49322514713 = 192595921827
BaseRepresentation
bin101101111011110110…
…011101100100011001
311201022101000100112012
4231323312131210121
51302003030432323
634354120355305
73364154312663
oct557366354431
9151271010465
1049322514713
1119a1030135a
129686015b35
1348605b4564
14255c777533
15143a16d678
hexb7bd9d919

49322514713 has 4 divisors (see below), whose sum is σ = 51918436560. Its totient is φ = 46726592868.

The previous prime is 49322514707. The next prime is 49322514719. The reversal of 49322514713 is 31741522394.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is an interprime number because it is at equal distance from previous prime (49322514707) and next prime (49322514719).

It is a cyclic number.

It is not a de Polignac number, because 49322514713 - 26 = 49322514649 is a prime.

It is a super-2 number, since 2×493225147132 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (49322514719) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1297960895 + ... + 1297960932.

It is an arithmetic number, because the mean of its divisors is an integer number (12979609140).

Almost surely, 249322514713 is an apocalyptic number.

It is an amenable number.

49322514713 is a deficient number, since it is larger than the sum of its proper divisors (2595921847).

49322514713 is a wasteful number, since it uses less digits than its factorization.

49322514713 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2595921846.

The product of its digits is 181440, while the sum is 41.

The spelling of 49322514713 in words is "forty-nine billion, three hundred twenty-two million, five hundred fourteen thousand, seven hundred thirteen".

Divisors: 1 19 2595921827 49322514713