Base | Representation |
---|---|
bin | 1110010110110111010… |
… | …01010111010001000001 |
3 | 1202011022201021211102001 |
4 | 13023123221113101001 |
5 | 31040300144401444 |
6 | 1014342445424001 |
7 | 50432500036021 |
oct | 7133351272101 |
9 | 1664281254361 |
10 | 493311325249 |
11 | 180237423126 |
12 | 7b734b6b001 |
13 | 376994a9772 |
14 | 19c3ab87a81 |
15 | cc738138d4 |
hex | 72dba57441 |
493311325249 has 2 divisors, whose sum is σ = 493311325250. Its totient is φ = 493311325248.
The previous prime is 493311325229. The next prime is 493311325253. The reversal of 493311325249 is 942523113394.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 344475086400 + 148836238849 = 586920^2 + 385793^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-493311325249 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 493311325199 and 493311325208.
It is not a weakly prime, because it can be changed into another prime (493311325229) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 246655662624 + 246655662625.
It is an arithmetic number, because the mean of its divisors is an integer number (246655662625).
Almost surely, 2493311325249 is an apocalyptic number.
It is an amenable number.
493311325249 is a deficient number, since it is larger than the sum of its proper divisors (1).
493311325249 is an equidigital number, since it uses as much as digits as its factorization.
493311325249 is an evil number, because the sum of its binary digits is even.
The product of its digits is 699840, while the sum is 46.
It can be divided in two parts, 493311 and 325249, that added together give a triangular number (818560 = T1279).
The spelling of 493311325249 in words is "four hundred ninety-three billion, three hundred eleven million, three hundred twenty-five thousand, two hundred forty-nine".
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