Base | Representation |
---|---|
bin | 100011111001111110011… |
… | …1011111000111101011001 |
3 | 122110202202022000210220212 |
4 | 1013303330323320331121 |
5 | 1121323101144422131 |
6 | 14255013545100505 |
7 | 1016350403005265 |
oct | 107637473707531 |
9 | 18422668023825 |
10 | 4934866014041 |
11 | 16329572388a7 |
12 | 6784b0787735 |
13 | 29a481ac5682 |
14 | 130bc51150a5 |
15 | 885793eca2b |
hex | 47cfcef8f59 |
4934866014041 has 2 divisors, whose sum is σ = 4934866014042. Its totient is φ = 4934866014040.
The previous prime is 4934866014037. The next prime is 4934866014049. The reversal of 4934866014041 is 1404106684394.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 4895616460816 + 39249553225 = 2212604^2 + 198115^2 .
It is a cyclic number.
It is not a de Polignac number, because 4934866014041 - 22 = 4934866014037 is a prime.
It is not a weakly prime, because it can be changed into another prime (4934866014049) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2467433007020 + 2467433007021.
It is an arithmetic number, because the mean of its divisors is an integer number (2467433007021).
Almost surely, 24934866014041 is an apocalyptic number.
It is an amenable number.
4934866014041 is a deficient number, since it is larger than the sum of its proper divisors (1).
4934866014041 is an equidigital number, since it uses as much as digits as its factorization.
4934866014041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1990656, while the sum is 50.
The spelling of 4934866014041 in words is "four trillion, nine hundred thirty-four billion, eight hundred sixty-six million, fourteen thousand, forty-one".
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